Math is a tough subject for students probably because it is one subject that you can't just learn by reading out of a book. To understand it completely, you have to practice. A major issue that students face is that, once they have solved a set of questions, they need someone to check their work and correct any mistakes. Students can find plenty of 6th grade math questions and answers online on math help sites. Here they will find practice questions for any topic, ranging from simple to very hard math problems.

## 6th Grade Math Word Problems with Answers

### Solved Examples

**Question 1:**The sum of three consecutive even numbers is 48. What is the largest of these numbers?

**Solution:**

Let three consecutive integer be x, x + 2, x + 4

Sum of three consecutive integers = 48

=> x + (x + 2) + (x + 4) = 48

=> x + x + 2 + x + 4 = 48

=> 3x + 6 = 48

When a number is added to a variable, subtract that number.

Subtract 6 from each side of the equation

=> 3x + 6 - 6 = 48 - 6

=> 3x = 42

Divide each side by 3

=> $\frac{3x}{3} = \frac{42}{3}$

=> x = 14

First integer = 14

Second integer = x + 2 = 14 + 2 = 16

Third integer = x + 4 = 14 + 4 = 18

Hence, the larger integer = 18.

Step1:Step1:

Sum of three consecutive integers = 48

=> x + (x + 2) + (x + 4) = 48

=> x + x + 2 + x + 4 = 48

=> 3x + 6 = 48

Step 2:Step 2:

When a number is added to a variable, subtract that number.

Subtract 6 from each side of the equation

=> 3x + 6 - 6 = 48 - 6

=> 3x = 42

Divide each side by 3

=> $\frac{3x}{3} = \frac{42}{3}$

=> x = 14

Step 3:Step 3:

First integer = 14

Second integer = x + 2 = 14 + 2 = 16

Third integer = x + 4 = 14 + 4 = 18

Hence, the larger integer = 18.

**answer****Question 2:**Sumalee had some candy to give to her five children. She first took six pieces for herself and then evenly divided the rest among her children. Each child received two pieces. With how many pieces did she start.

**Solution:**

Let Sumalee have x number of candies.

Number of pieces she took for herself = 6

Remaining candies are = x - 6

Number of pieces received by each child = 2

The problem states:

She had divided (x - 6) candies among 5 children and each child got 2.

=> $\frac{x - 6}{5}$ = 2

Solve for x,

=> $\frac{x - 6}{5}$ = 2

=> x - 6 = 10

Add 6 to each side

=> x - 6 + 6 = 10 + 6

=> x = 16

Hence she had 16 candies.

Step 1:Step 1:

Number of pieces she took for herself = 6

Remaining candies are = x - 6

Number of pieces received by each child = 2

Step 2:Step 2:

The problem states:

She had divided (x - 6) candies among 5 children and each child got 2.

=> $\frac{x - 6}{5}$ = 2

Step 3:Step 3:

Solve for x,

=> $\frac{x - 6}{5}$ = 2

=> x - 6 = 10

Add 6 to each side

=> x - 6 + 6 = 10 + 6

=> x = 16

Hence she had 16 candies.