Practice is the most effective way to gain proficiency in math. Practicing math problems is the best way to ingrain math formulas and steps so that you can solve any problem you get during tests. Online 6th grade math problems get easy when you do lots of practice questions. In fact, 6th grade math problems online are fun and use interactive tools so that solving math problems is interesting and students learn quickly. You will find that math problem for 6th grade covers all the topics in math that students learn in class. 

Math Problems For 6th Grade

Many websites have separate topics according to different state curriculum to make finding problems for a particular subject easier. Online 6th grade math problems have varied difficulty levels so that students will a comfortable level to start with before progressing to tougher questions. Hard 6th grade math problems can provide an exciting challenge to students who have a good aptitude for the subject and want to learn more. 6th grade math problems are easy to use and convenient to access and students will soon enjoy learning math.

Solved Examples

Question 1: Find the value of  'm'.

18m - 108x = 6m, for x = 1.

Solution:
Step 1:
Given 18m - 108x = 6m

Solve the equal terms, Subtract 6m from both sides

=> 18m - 108x - 6m = 6m - 6m

=> 12m - 108x = 0

Step 2:

To find the value of m, put x = 1

=> 12m - 108 * 1 = 0

=> 12m - 108 = 0

Add 108 to both sides

=> 12m - 108 + 108 = 108

=> 12m = 108
Divide each side by 12

=> $\frac{12m}{12} = \frac{108}{12}$

=> m = 9. answer

 

Question 2: Find the least common multiple of 24, 32 and 48.

Solution:
Prime Factors of 24 = 2 x 2 x 2 x 3

Prime Factors of 32 = 2 x 2 x 2 x 2 x 2

Prime Factors of 48 = 2 x 2 x 2 x 2 x 3

=> LCM(24, 32, 48) = 2 x 2 x 2 x 2 x 2 x 3 = 96

=> LCM(24, 32, 48) = 96. answer
 

Question 3: Find the product of $\frac{3}{4}$ and $\frac{4}{6}$.
Solution:
Step 1:  Multiply the numerators

3  x 4 = 12

Step 2:
Multiply the denominators

4 x 6 = 24

Step 3:

$\frac{3}{4}$ x $\frac{4}{6}$ = $\frac{12}{24}$

Step 4:
Reduce $\frac{12}{24}$,

=> $\frac{12}{24}$ = $\frac{2 * 2 * 3}{2 * 2 * 2 * 3}$

= $\frac{1}{2}$

=> $\frac{12}{24}$ is reduced as $\frac{1}{2}$. answer