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# 6th Grade Math Test

Doing math tests regularly is a great way to find out how well you know your subject. 6th grade math practice tests online are popular among students who take these tests to check how much they have learned or improved. Being online, math tests for 6th grade offers a great deal of flexibility, allowing students to take them whenever they need to. Online 6th grade math tests also record previous test scores, giving users a snapshot of their improvement over time.

## 6th Grade Math Test

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6th grade math test online has different types of tests which cover all the different areas of math which students are taught in the 6th grade. Apart from improving performance and showing students areas they need to work on, practicing online math tests also helps students get ready for their exams. 6th grade math test prep ensures that you are always ready for any surprise tests and quizzes, which may come up in class. Mock 6th grade online math tests can ensure that you ace the real tests!

### Solved Examples

Question 1: Find the area of a rectangle with the length of 13 mtrs and width of 12 mtrs.

Solution:
Given:
Length of a rectangle = 13

Width of a rectangle = 12

Area of rectangle = Length * width

=> Area of rectangle =13 * 12

1 3
x 1 2
----------
2 6
1 3 x
----------
1 5 6
----------

=> Area of rectangle = 156 square mtr.

Question 2: Solve $2\tfrac{1}{3}$ x $3\tfrac{4}{3}$
Solution:
Step 1:
Convert mixed fraction into improper fraction

$2\tfrac{1}{3}$ = $\frac{7}{3}$

$3\tfrac{4}{3}$ = $\frac{13}{3}$

=> $2\tfrac{1}{3}$ x $3\tfrac{4}{3}$ = $\frac{7}{3}$ x $\frac{13}{3}$

Step 2:

Multiply the numerators

7 x 13 = 91

Multiply the denominators
3 x 3 = 9

Step 3:

=> $\frac{7}{3}$ x $\frac{13}{3}$ = $\frac{91}{9}$

Hence $2\tfrac{1}{3}$ x $3\tfrac{4}{3}$  is reduced to $\frac{91}{9}$.

Question 3: 7545 is divisible by 3 ?

Solution:
Step 1:
Every number the sum of whose digits will exactly divided by 3, is divisible by 3.

=> 7545 = 7 + 5 + 4 + 5 = 21

Step 2:

The sum of the digits of the number = 21, which sum being divisible by 3.

[3 * 7 = 21]

=> 7545 is divisible by 3.