6th grade math word problems can be very challenging but so satisfying when you know you’ve finally got them right! You might as well get used to solving them because they’re going to keep showing up in every grade. The key to solving them is to identify the information you need and ignore the rest. Since these problems are expressed in words, there will naturally be a lot of information, not all of which you need. So how do you learn to sort out the facts you need and solve the problem quickly? This is where online help for 6th grade math word problems comes in. Get all the help you need with a few clicks of the mouse.

## 6th Grade Math Word Problem

Online math help has experienced tutors and loads of different
kinds of word problems for students to try their hand at. 6th grade math formulas and math online
helpers make math easy and fun while ensuring students learn the
concepts and understand them. There are real life examples where
students need to apply math and tutors are willing to explain any number
of times. Online help is a great way for students to learn how to solve
6th grade math word problems quickly and easily.

## Solved Examples

**Question 1:**The perimeter of an isosceles triangle is 24 cm and length of one of the sides is 4 cm. Find the lengths of the other two equal sides.

**Solution:**

Let the lengths of equal sides of the triangle = a

and length of other side of the triangle = b = 4

Given, perimeter of isosceles triangle = 24

Perimeter of isosceles triangle = 2a + b

=> 2a + b = 24

=> 2a + 4 = 24

Subtract 4 from both sides

=> 2a + 4 - 4 = 24 - 4

=> 2a = 20

Divide each side by 2

=> $\frac{2a}{2} = \frac{20}{2}$

=> a = 10

Hence the lengths of the other two equal sides = 10 cm

and length of other side of the triangle = b = 4

**Step 1:**Given, perimeter of isosceles triangle = 24

Perimeter of isosceles triangle = 2a + b

=> 2a + b = 24

=> 2a + 4 = 24

**Step 2:**

Solve for a,Subtract 4 from both sides

=> 2a + 4 - 4 = 24 - 4

=> 2a = 20

Divide each side by 2

=> $\frac{2a}{2} = \frac{20}{2}$

=> a = 10

Hence the lengths of the other two equal sides = 10 cm

**Question 2:**What is the length of the wooden strip required to frame a photograph of length and breadth 42 cm and 38 cm respectively.

**Solution:**

**Step 1:**

Given

Length of the photograph = 42 cm

Given

Breadth of the photograph = 38 cm

**Step 2:**

Photograph is of the shape of rectangle.

[ Perimeter of rectangle = 2(Length + Breadth) ]

Length of wooden strip required = Perimeter of photograph

= 2(Length + Breadth)

= 2(42 + 38)

= 2 * 80

= 160

Hence, required length of the wooden strip is 160 cm.

**answer**

**Question 3:**Water boils at a temperature of 100 degree Celsius. At what temperature Fahrenheit does water boil.

**Solution:**

**Step 1:**

Given

Boiling point of water = 100

^{0}C

**Step 2:**

Change the temperature on the Celsius scale to temperature on the Fahrenheit scale.

[ F = 1.8 * C + 32 ]

=> F = 1.8 * C + 32

=> F = 1.8 * 100 + 32

=> F = $\frac{18}{10}$ * 100 + 32

=> F = 180 + 32

=> F = 212

The Fahrenheit temperature at which water boils is 212

^{0}F.

**answer**